Question

give answered fast I need solution


Um A contains 6 red and 4 black balls and urn B contains 4 red and 6 black balls . one ball is drawn at random from urnA and placed in turn B . then one ball is drawn at random form urn B and placed in urn A . if one ball is drawn at random from urn A the probability that it is found to be red is .........

Answer 1

let R be drawing a red ball and B for drawing black ball required probility .


RRR + RBR+ BRR+ BBR


(6/10*5/11*6/10) (6/10*6/11*5/10) ( 4/10*4/11*7/10) ( 4/10*7/11*6/10)


= 640 / 1100


= 32/55


BE BRAINLY