Question

Give balanced chemical equations for all the steps involved in conversion of bauxite to alumina.

Answer 1

Explanation:

Al2O3 + 2 NaOH -----> 2NaAlO2 + H2O. Aluminium oxide reacts with Sodium hydroxide to give Sodium aluminate and water.

Al2O3 + 2 NaOH -----> 2NaAlO2 + H2O. Aluminium oxide reacts with Sodium hydroxide to give Sodium aluminate and water.2NaAlO2 + H2O -----> Al(OH)2 + NaOH. ...

Al2O3 + 2 NaOH -----> 2NaAlO2 + H2O. Aluminium oxide reacts with Sodium hydroxide to give Sodium aluminate and water.2NaAlO2 + H2O -----> Al(OH)2 + NaOH. ...Al(OH)2 + Heat ----> Al2O3 + H2O

Answer 2

$\huge\rm\underline\purple{Question :-}$

Give balanced chemical equations for all the steps involved in conversion of bauxite to alumina.

$\large{\underbrace{\sf{\red{ Required\:Solution:}}}}$

Balanced chemical equations for all the steps involved in conversion of bauxite to alumina are as follows:

$\boxed{ \sf \green{ First\: step: }}$

$Al_2O_{3(s)}+2NaOH{(aq)}+3H_2O{(l)}\underset{35-36 bar}{\xrightarrow{\text{473-523 K}}} 2Na[Al(OH)_4]{(aq)}$

$\boxed{ \sf \blue{ Second\: step: }}$

$2Na[Al(OH)_4]+CO_2{(s)}\underset{35-36 bar}{\xrightarrow{\text{473-523 K}}} Al_2O_3.xH_2O+2NaHCO_3$

$\boxed{ \sf \pink{ Third\: step: }}$

$Al_2O_3.xH_2O \overset{1407K}{\longrightarrow}</p><p></p><p>Al_2O_3+xH_2O$

✯Note:

$\orange{\underline\bold{Here,}}$

✏ $Al_2O_{3(s)}$is $\red{\underline\bold{Bauxite.}}$

✏ $2Na[Al(OH)_4]{(aq)}$ is $\red{\underline\bold{Sodium \:aluminate.}}$

✏ $Al_2O_3$ is $\red{\underline\bold{Pure \:alumina.}}$

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