give defination for transposing and without transposing methods
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Answer:
THE TRANSPOSING METHOD IN SOLVING LINEAR EQUATIONS
(Basic Step to improve math skills of high school students)
(by Nghi H. Nguyen – Jan 06, 2015)
Most of the immigrant students who first began learning Algebra I in US high schools found the
existing linear equation solving process very different from what they had learned in their
countries.
Let’s see what the differences are and how can the existing solving process be improved?
The basic difference shows itself in the way we teach students on how to solve a linear
equation by balancing its two sides. In addition, we teach them doing the solving in various
steps: simple step for simple equation, two steps for complex one, and multiple steps for more
complicated equations.
In contrary, the world wide solving process, a process called Transposing Method, performs by
moving (transposing) terms from one side to the other side of an equation.
The two different processes are generally explained below then they are compared one to the
other through selected examples.
SOLVING LINEAR EQUATIONS IN SIMPLE (ONE) STEP.
Example 1. Solve x – 5 = 2
Solution. +5 +5
x = 7
We teach students to add +5 by writing +5 in both sides of the equation, one line down from
the equation line. This practice comes from the concept of balancing the 2 sides of the
equation. Some math books write +5 on both sides of the equation, on the same equation line:
x – 5 + 5 = 2 + 5
x = 7
Example 2. Solve: 3x = 9
Solution. 3x = 9
:3 :3
x = 3
Students are taught to write (:3) on both sides of the equations, one line down from the
equation line. Some books tell students to multiply by (1/3) on both sides.
3x = 9
3x .(1/3) = 9.(1/3)
x = 3
Example 3. Solve 5x/11 = 3
Solution. Students are taught to divide the 2 sides by the fraction (5/11), meaning to multiply
by the inverse of the fraction (5/11) that is the fraction (11/5).
5x/11.(11/5) = 3.(11/5)
x = 33/
Step-by-step explanation:
HOPE THIS IS HELFULL!
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