Give Formula of magnetic dipole moment of Circular Coil Carrying current.
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The dipole moment of a circular loop carrying a current I , is m and the magnetic field at the centre of the loop is B1. When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is B2. The ratio B1B2 is: (A) √2.
- The magnetic dipole moment of the current loop is equal to the product of ampere-turns and area of current loop.
- The magnetic dipole moment of the current loop is equal to the product of ampere-turns and area of current loop.
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Answer:
The formula of the magnetic dipole moment of circular coil carrying current is, m = nIA
Explanation:
- A magnetic moment also referred to as a magnetic dipole moment, is a measurement of an object's tendency to align with a magnetic field.
- The magnetic pull and direction of a magnet or other item that generates a magnetic field are known as the "Magnetic Moment" A vector quantity is a magnetic moment.
- The vector whose magnitude is equal to the area of the loop times the magnitude of the current flowing through it (m = IA) and whose direction is perpendicular to the plane in which the current flows is the magnetic moment m of a current loop.
- It is mathematically expressed as- m = nIA where n is the number of loops, I is current and A is the area
- ∵ The area of the circle is πr²
- Therefore, the Magnetic moment becomes, m = nIπr²
Thus, The formula of the magnetic dipole moment of circular coil carrying current is, m = nIA
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