give me a answer in method
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so , a= 3 given
and b=-2
1. a^a + b^b
=(3^3 ) + (-2)^(-2)
=27 + (1/-2)^2
=27 + 0.25
=27.25
2. a^b + b^a
=(3^(-2)) + (-2)^(3)
=(1/9) + (-8)
=1/9 - 8
3. (a+b)^ab
= ( 3 + (-2) ) ^ (3)(-2)
=(1)^(-6)
=1
and b=-2
1. a^a + b^b
=(3^3 ) + (-2)^(-2)
=27 + (1/-2)^2
=27 + 0.25
=27.25
2. a^b + b^a
=(3^(-2)) + (-2)^(3)
=(1/9) + (-8)
=1/9 - 8
3. (a+b)^ab
= ( 3 + (-2) ) ^ (3)(-2)
=(1)^(-6)
=1
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