How many way a 4digit number can be arrange using 0 0 1 2 3?
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ShohelAhmod:
I'm not clear about calculation.
Is answer correct?
I'm not sure but assuming incorrect.
How many way a 4digit number can be arrange using 0 0 1 2 3?
Solution:
4C4*(4!-3!)+3C2*(4!-3!-2!)
=(24-6)+3(24-6-2)
=18+48
=68
ans. 68
Solution:
4C4*(4!-3!)+3C2*(4!-3!-2!)
=(24-6)+3(24-6-2)
=18+48
=68
ans. 68
assuming!! wow
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