give me a answer please fast
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Here |z| =2.
Let it be r →|z|=r=2.
Now Arg(z)=π/4=45°
But arg(z) is the angle Theta.
Let this be x.
→Arg(z)=x=45°
z=r[cos(x) + i sin(x)]
→z=2[cos45° + i sin45°]
→z=2[1/√2 +i × 1/√2]
→z= 2/√2 + i/√2
So Here Re(z)=2/√2 and Im(z)=1/√2
Hope it Helps...
Regards,
Leukonov.
Let it be r →|z|=r=2.
Now Arg(z)=π/4=45°
But arg(z) is the angle Theta.
Let this be x.
→Arg(z)=x=45°
z=r[cos(x) + i sin(x)]
→z=2[cos45° + i sin45°]
→z=2[1/√2 +i × 1/√2]
→z= 2/√2 + i/√2
So Here Re(z)=2/√2 and Im(z)=1/√2
Hope it Helps...
Regards,
Leukonov.
muskan6216:
thank you so much
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