give me ans of 4th question
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The ratio of angles are 3:4:5:6
let the angles be- 3x+4x+5x+6x
3x+4x+5x+6x=360°. (sum of angles of quadrilateral is 360°)
18x=360°
x=360÷18
x=20
so,
3x=60°
4x=80°
5x=100°
6x=120°
prove AB || CD
angle BAD+ angle BCD
60°+120°= 180°
We know that sum of opposite angles of ||gm is 180°. And OPPOSITE sides of parallelogram are parallel. HENCE AB ||CD.
HENCE PROVED
let the angles be- 3x+4x+5x+6x
3x+4x+5x+6x=360°. (sum of angles of quadrilateral is 360°)
18x=360°
x=360÷18
x=20
so,
3x=60°
4x=80°
5x=100°
6x=120°
prove AB || CD
angle BAD+ angle BCD
60°+120°= 180°
We know that sum of opposite angles of ||gm is 180°. And OPPOSITE sides of parallelogram are parallel. HENCE AB ||CD.
HENCE PROVED
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