Question

give me answer.....?​

Answer 1

Answer:

the answer is 105°......

Answer 2

$\bold{Question}$

Two chords AB and CD of a circle cut each other when produced outside the circle at P. AD and BC are joined. If ∠PAD=30 and ∠CPA=45 Find ∠CBP.

Solution

$\bold{∠PAD=∠PCB=30°}$

$\bold{In △CBP}$

$\bold{∠C+∠P+∠B=180° }$

$\bold{=30 +45 +∠B=180° }$

$\bold{∠B=180° −75° }$

$\bold{∠B=105° }$

$\bold{∠CBP=105° }$

hope it helps ☺️☺️