give me answer of question no 21
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area of triangle = √3/4 x s^2
(36√3 x 4)/√3 = s^2
144 = s^2
s = 12
length = 12 + 12 + 12 = 36 cm
When bent into a square all sides are = therefore a = 36/4 = 9
area of square = a^2
= 9 x 9 = 81 cm^2
When bent into a rectangle opp sides are equal
l = 10 and b = 8
10 + 10 = 20
8 + 8 = 16
20 + 16 = 36
and l is 2 cm greater than b
area = lb = 8 x 10 = 80 cm^2
(36√3 x 4)/√3 = s^2
144 = s^2
s = 12
length = 12 + 12 + 12 = 36 cm
When bent into a square all sides are = therefore a = 36/4 = 9
area of square = a^2
= 9 x 9 = 81 cm^2
When bent into a rectangle opp sides are equal
l = 10 and b = 8
10 + 10 = 20
8 + 8 = 16
20 + 16 = 36
and l is 2 cm greater than b
area = lb = 8 x 10 = 80 cm^2
rwnu:
thnk u so much for this answer
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