Math, asked by gurreetpreet, 1 year ago

give me answer of this question
tomorrow will be my paper please
urgent ​

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Answered by sriram979
1

now

(3√2/√6-√3)+(2√3/√6+2)-(4√3/√6-√2)

=(3√2/√3(√2-1))+(2√3/√2(√3+√2))-(4√3/√2(√3-1))

=(√6/√2-1)+(√6/√3+√2)-(2√6/√3-1)

=(√6(√2+1)/2-1)+(√6(√3-√2)/3-2)-(2√6(√3+1)/3-1)

=(√12+√6/1)+((√18-√12)/1)-(2√18+2√6/2)

=√12+√6+√18-√12-√18-√6

all get cancel answer is 0


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Answered by ansh6385
5

Answer:

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