give me answer please my dear siso or bro... prove it
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Answer:
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Answered by
1
Answer:
cos20°.cos40°.cos60°.cos80°
=1/2(2cos40°cos20°)1/2.cos80
2CosAcosB=(cos(A+B)+cos(A-B)
=1/4{(cos(40+20)+cos(40-20))}cos80
=1/4{cos60+cos20}cos80
=1/4{cos80.cos60+cos80.cos20}
=1/4{1/2.cos80+1/2(cos(80+20)+cos(80-20)}
=1/8{cos80+cos100+cos60}
=1/8{cos80+cos(180-100)+cos60}
=1/8{cos80-cos80+cos60}
=1/8x1/2
=1/16
hope this helps you
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