Math, asked by singhravi980knp, 7 months ago

Give me answers help me
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Answers

Answered by karwakaruna90
1

Answer:

angle ABC=42°

angle ACB=105°

Step-by-step explanation:

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Answered by anushreemodi08
0

Answer:

HOPE IT HELPS!!

Step-by-step explanation:

BAC=33°, CBD=138°

ACB=CBD-BAC [ EXTERIOR ANGLE IS THE SUM OF TEO OPPOSITE ANGLES]

       =138° -33°

       =105°

ABC+ACB+BAC=180°[ SUM OF ALL ANGLES OF A TRIANGLES]

ABC+105°+33° =180°

ABC=180°-138°

       =   42°

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