Question

give me right answer and question is in photo ​

Answer 1

here is ur answer.............

first we have to find its zeroes using spliting the middle term method..............

==> $x^{2} -4x +3$

==> $x^{2} -3x-x +3$

==> $x(x-3)-1(x-3)$

==>  x=1 and x = 3

so, two zeroes are 1 and 3 ........

i.==> $(1)^{2} + (3)^{2}$  

==> 1 + 9

==> 10

ii.  ==> $1^{3} + 3^{3}$

==> 1 + 27

==> 28

hope u got ur answer...........

keep smiling and be happy......................

Answer 2

Answer:

hi. hello...how are u inbox kar do plz