give me soluation fastly
Answers
Answer:
4) Given:-
Voltage = 9V
Resistor (R1) = 0.2ohm
Resistor (R2) = 0.3ohm
Resistor (R3) = 0.4ohm
Resistor (R4) = 0.5ohm
Resistor (R5) = 12ohm
To find:-
Current flowing through 12ohm resistor
By applying I = V/R
= 9/12
= 0.75Amp.
5) Given:-
Resistor (R1) = 20ohm
Resistor (R2) = 4ohm
Voltage = 6V
To find:-
a) Total resistance of circuit
We know that resistors are connected in series
Req = R1+R2
= 20+4
= 24ohm.
b) Current through the circuit
By applying, I = V/R
= 6/24
= 0.25Amp.
c) Potential difference across the electric bulb
By applying, V = IR
= 0.25×20
= 5V.
d) Potential difference across the resistance wire
By applying, V = IR
= 0.25×4
= 1V.
6) Given:-
Resistor (R1) = 5ohm
Resistor (R2) = 10ohm
Through the 5 ohm resistor current of 1 Amp is flowing
i) What is the current through the other two resistors
We know that Resistors R2 and R3 are connected in parallel
So, Req = 1/R1+1/R2
= 1/10+1/15
= 10×15/10+15
= 6ohm.
By applying V = IR
= 1×6 = 6V.
i) Current flowing through 10ohm
By applying I = V/R
= 6/10
= 0.6Amp.
Current flowing through 15ohm
By applying I = V/R
= 6/15
= 0.4Amp.
ii) Potential difference across AB
By applying V = IR
= 1×5 = 5V.
Potential difference across AC
By applying V = IR
= 1×6 = 6V.
iii) Total resistance
Req = R1+R2
= 5+6
= 11ohm.