give me the ans of question 5
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apply formula of csa of cuboid and then u'll find the answer.
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adi1474:
LSA=2(l+b)h+l×b
this right
no this is wrong
pagal ho kaya beta
LSA = 2h(l+b)
this is correct
LSA=2(l+b)*h
you can check on google
right
ok
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l = 12m
b=8m
h=4m
First , whitewashing of all four walls of a room=LSA of a cuboid
LSA of a cuboid = 2h(l+b) sq . un
= 2×4(12+8) m^2
= 8(20).
=120m^2
cost of whitewashing = 120×5
= ₹ 600
Area of the ceiling of the room = area of a rectangle
Area of a rectangle = l×b sq . u
= 12×8
= 96 m ^2
Area of 4 walls + Area of the ceiling = 120 + 96m^2
=216m^2
cost of whitewashing 4 walls and ceiling =216×5= ₹ 1080
b=8m
h=4m
First , whitewashing of all four walls of a room=LSA of a cuboid
LSA of a cuboid = 2h(l+b) sq . un
= 2×4(12+8) m^2
= 8(20).
=120m^2
cost of whitewashing = 120×5
= ₹ 600
Area of the ceiling of the room = area of a rectangle
Area of a rectangle = l×b sq . u
= 12×8
= 96 m ^2
Area of 4 walls + Area of the ceiling = 120 + 96m^2
=216m^2
cost of whitewashing 4 walls and ceiling =216×5= ₹ 1080
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