give me the answer of question number 4 please
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Let the principal be ₹x
For the first year ,
C.I= (P*R*T)/100
=(x*20*1)/100
=₹x/5
For the 2nd year ,
Principal = p of first yr + CI of first yr
=x+x/5
=6x/5
C.I = PRT/100
= 6x/5*20*1/100
= 6x/25
ATQ,
6x/25 + x/5 = 3520
(6x+5x)/25 = 3520
11x = 3520*25
x = ₹ 8000
The principal is ₹8000
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For the first year ,
C.I= (P*R*T)/100
=(x*20*1)/100
=₹x/5
For the 2nd year ,
Principal = p of first yr + CI of first yr
=x+x/5
=6x/5
C.I = PRT/100
= 6x/5*20*1/100
= 6x/25
ATQ,
6x/25 + x/5 = 3520
(6x+5x)/25 = 3520
11x = 3520*25
x = ₹ 8000
The principal is ₹8000
Plzzz mark as brainliest
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