Question

give me the answers please​

Answer 1

Answer:

In ∆ABD, ADB=90°

AB^2=AD^2+BD^2. (Pythagoras theorem)

(10)^2=(6)^2+BD^2

100=36+BD^2

So, BD=√100-36=√64= 8 cm

BC=BD+CD

=BD+BD. (BD=CD)

=8+8

=16 cm

Similarly, In ∆ACD , ADC=90°

So, AC=10cm using Pythagoras theorem.