Question

Give me the solution of this question

Answer 1

this is ur answer "Math boom". 249πcm^2

Answer 2

Radius (r1) of upper circular end of frustum part = 18/2 = 9 cm

Radius (r2) of lower circular end of frustum part = Radius of circular end of cylindrical part = 8/2 = 4 cm

Height (h1) of frustum part = 22 − 10 = 12 cm Height (h2) of cylindrical part = 10 cm

Slant height (l) of frustum part 

$\sqrt{(9 - 4) { }^{2} } + 12 \\ = 13$


Area of tin sheet required = CSA of frustum part + CSA of cylindrical part