Question

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A bag contains one rupee 50 paisa and 25 paisa coins in the ratio 5:6:8 amounting to rs.210 . Find the no.of coins of each type . Help me coz tomorrow is my EXAM...
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Answer 1

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Brainly.in

Secondary SchoolMath 13 points

A bag contains rupee, 50 paise and 25 paise coins in the ratio 5:6:8. if the total amount is rs 420 find the number of coins of each type

Ask for details Follow Report by Subrata6476 24.05.2018

Answers

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anushaomk1234

anushaomk1234 Helping Hand

Let the no. Of Rs1,50p, and 25p coins be 5x, 6x, 8x.

Total value of coins = Rs( 5x × 1+ 6x × 50/100+8x × 25/100)

= Rs(5x/30 + 3x/30 + 2x/30) {taking l.c.m as 30}

=Rs(10x/30)

But ,the total value of the coin is= Rs 420

Therefore,

10x/30 = 420

=> x= ( 420× 30/10)

=> x= 1260

Number of RS 1 coins = 5x= (5×1260) = 6300

No. Of 50 p coins = 6x=(6×1260) =7560

No of 25 p coins = 8x = (8×1260) = 10080

#Dramqueen⭐

Answer 2

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