Question

if triangle ABC and AMP are right angle at B and M respectively. prove that CA×MP=PA×BC​

Answer 1

Answer:

Step-by-step explanation:

ABC~AMP

Angle A is common

Angle B =AngleM (90)

AB/AM=BC/MP=AC/AP

BC/MP=AC/AP

MPXAC=BCXAP

Answer 2

Ans

angle b = angle m=90

angle a= angle a common

so both triangles are similar

from bpt ca\pa=bc\mp

on cross multiplication ca*mp=pa*bc

hence proved