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IN A EQUILATERAL TRIANGLE
AB = BC
BC=CA
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AB=BC=CA
<A=<B=<C
We know that sum of angles of a triangle is 180 degree
<A+<b+<C = 180 DEGREE
<a+<a+<a = 180 (<a=<b=<C)
3<A = 180
<a = 60 DEGREE
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<A=<B<C= 60 DEGREE proved
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