Question

Give p(0),(1)and p (2) for p(t)=2+t+2t²-t³​

Answer 1

Answer:

P(t)=2+t+2t2-t3 then the values of p(0),p(1),p(2) are respectively

p(t)=2+t+2t2-t3

p(0)=2+0+2*0*2-0*3

=2

p(1)=2+1+2*1*2-1*3

=4

p(2)=2+2+2*2*2-2*3

=9