Give reason( no frauds only correct information...)
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as we the ohms law
according to this law I proportional to V
and finally V=IR here R is proportionally constant. and this relation is also in the form of Y=mX , where m is slope (m=tantheta)
same as R is a slope of given V-I graph
value of R is greater then angle is also greater
and when length, area are same for both wire
then due to the relation R= resistivity×(length/area) R is fully depending upon the resistivity.
so our final answer is A has high resistivity because it has greatest angle.
OK now u understand well.
according to this law I proportional to V
and finally V=IR here R is proportionally constant. and this relation is also in the form of Y=mX , where m is slope (m=tantheta)
same as R is a slope of given V-I graph
value of R is greater then angle is also greater
and when length, area are same for both wire
then due to the relation R= resistivity×(length/area) R is fully depending upon the resistivity.
so our final answer is A has high resistivity because it has greatest angle.
OK now u understand well.
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