CBSE BOARD XII, asked by sairamavishal, 9 months ago

Give relation between the charges induced in a coil when it is rotated from teta=0 and teta=90 in a magnetic field of strength B having N turns and radius "r" .

Answers

Answered by ash7543
1

Answer:

it is happen because of the 1st charge from atmosphere 2nd from water 3rd from soil

Answered by nirman95
7

To find:

Charge induced in the coil when it is rotated from \theta = 0° to 90° in a magnetic field of strength be with N turns and radius r.

Calculation:

Faraday's Law of Electromagnetic Induction states EMF induced in a coil is equal to the the rate of change of magnetic flux.

 \therefore \: V =  \dfrac{d \phi}{dt}

Let area of coil be A:

 =  >  \: V =  \dfrac{NBA \{ \sin(90  \degree) -  \sin(0 \degree) \}  }{dt}

 =  >  \: V =  \dfrac{NBA \{ 1 -  0 \}  }{dt}

 =  >  \: V =  \dfrac{NBA   }{dt}

Current in the coil be I and resistance be R;

 =  >  \: I =  \dfrac{V}{R}

 =  >  \: I =  \dfrac{NBA   }{dt \times R}

Let charge be q ;

 \therefore \: q = I \times dt

 =  >  \: q=  \dfrac{NBA   }{dt \times R}  \times dt

 =  >  \: q=  \dfrac{NBA   }{ R}

So, final answer is:

 \boxed{ \bold{ \large{ \: q=  \dfrac{NBA   }{ R}  }}}

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