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given 2^x=3^x
adding log on both sides
xlog2=xlog3
which is possible only when x=0
so now 5x+2 = 5(0)+2
=2
hope this helps you
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Answered by
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Step-by-step explanation:
2^x=3^x
=>log(2^x)=log(3^x)
=>xlog(2)=xlog(3)
LHS and RHS can only be equal when x is 0 because log2 and log3 can never be same.
Well if you solve it also by finding the value of log then also the answer will be same
So, 5x+2=5(0)+2=0+2=2
so, here is your answer.
Hope it is satisfactory.
Have a nice day.
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