Give Solution of log10+log2-log 5+log 9+log 25=loga²
Answer = 30
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log10+log2-log 5+log 9+log 25=loga²
as log a + log b = log ab and log c - log d = log c/d.
so,
log10+log2-log 5+log 9+log 25=loga²
= log { (10 × 2 × 9 × 25)/ 5} = loga²
= log ( 2 × 2 × 9 × 25) = loga²
= log 900 = loga²
= log (30)² = loga²
(30)² = a²
root (30)² = a
30 = a
So, the value of a is 30.
as log a + log b = log ab and log c - log d = log c/d.
so,
log10+log2-log 5+log 9+log 25=loga²
= log { (10 × 2 × 9 × 25)/ 5} = loga²
= log ( 2 × 2 × 9 × 25) = loga²
= log 900 = loga²
= log (30)² = loga²
(30)² = a²
root (30)² = a
30 = a
So, the value of a is 30.
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