Question

Give solution of question. no. 2​

Answer 1

Answer:

17/√7 is the 15th term of AP

Step-by-step explanation:

let an= 17/√7

a=3/√7

d=a2-a1

= 4/√7-3/√7

=1/√7

an= a+(n-1)d

$\frac{17}{ \sqrt{7} } = \frac{3}{ \sqrt{7} } + (n - 1) \times \frac{1}{ \sqrt{7} }$

$\frac{17}{ \sqrt{7} } = \frac{3}{ \sqrt{7} } + \frac{n}{ \sqrt{7} } - \frac{1}{ \sqrt{7} }$

$\frac{17}{ \sqrt{7} } = \frac{2}{ \sqrt{7} } + \frac{n}{ \sqrt{7} }$

$\frac{17}{ \sqrt{7} } - \frac{2}{ \sqrt{7} } = \frac{n}{7}$

$\frac{15}{ \sqrt{7} } = \frac{n}{ \sqrt{7} }$

$\frac{15}{ \sqrt{7} } \times \sqrt{7} = n$

$n = 15$

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