Question

Give the ans with complete workout.​

Answer 1

Solution :-

$x {}^{(5 + a) {}^{2} } \times x {}^{(5 - a) {}^{2} } = x {}^{40}$

Apply ( n+m)² & ( n-m)² formula

Hence,

( 5+a) = 25 + a² + 10a

And ( 5-a) = 25 + a² - 10a

So,

$x {}^{25 + a {}^{2} + 10a } \times x {}^{25 + a {}^{2} - 10a } = x {}^{40}$

We know that -

$x {}^{c} \times x {}^{d} = x {}^{c + d}$

So,

$x {}^{25 + a {}^{2} + 10a + 25 + a {}^{2} - 10a } = x {}^{40}$

${x}^{50 + 2a {}^{2} } = x {}^{40}$

Now Apply Formula

$x {}^{ m} = x {}^{n}$

$m = n \: \:$

Hence,

$50 + 2a {}^{2} = 40$

$2a {}^{2} = 40 - 50 = -10$

$a = \sqrt{{-5}} \: \: \: \: \boxed{answer}$

Answer 2

Answer:

your answer is there are find jng the value