Math, asked by ranideviamit, 8 months ago

give the answer fast it is very urgent And explain every method step by step ​

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Answered by Glorious31
3

Question :

Write the power of the term (-6) in :

\tt{ {(-6)}^{8} ÷ {(-6)}^{3} = {(-6)}^{?}}

Answer :

If we carefully observe ; the given problem is in the form of the law of indices : \tt{ {a}^{m} ÷ {a}^{n} \implies {a}^{m-n}} . Where in this case (a) is (-6) and (m) is (8) and (n) is (3).

So , using the same identity ; we will solve the given problem.

\tt{ {a}^{m} ÷ {a}^{n} \implies {a}^{m-n}}

\tt{ {(-6)}^{8} ÷ {(-6)}^{3} \implies {(-6)}^{8 - 3}}

\tt{ {(-6)}^{8} ÷ {(-6)}^{3} \implies {(-6)}^{5}}

So , the answer is : \large{\boxed{\tt{ {(-6)}^{5}}}}

\tt{ {(-6)}^{5}} when further simplified gives us the number -7776.

More laws of indices :

  • \tt{ {a}^{m} + {a}^{n} \implies {a}^{m+n}}
  • \tt{ {a}^{-m} \implies \dfrac{1}{m}}
  • \tt{ {a}^{m} ÷ {a}^{n} \implies {a}^{m-n}}
  • \tt{ {({a}^{m})}^{n} \implies {a}^{m \times n}}
  • \tt{ {ab}^{m} \implies {a}^{m} \times {b}^{m}}
  • \tt{ {a}^{0} \implies 1}
  • \tt{ {a}^{1} \implies a}
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