Question

give the answer for this question

Answer 1

Hey mate..!!

Here you go..!!

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GIVEN- OM=3 cm and AB=8cm

TO DETERMINE--Radius of circle(AO)

FORMULA USED--
${h}^{2} = {b}^{2} + {p}^{2}$

PROOF--

In figure,OM is perpendicular to AB(Perpendicular drawn from the centre to a chord bisects it)..

Thus..AM=MB=4 cm

So..
Using pythagoras theorem in ∆AOM--

${AO}^{2} = {3}^{2} + {4}^{2} \\ {AO}^{2} = 9 + 16 \\ {AO}^{2} = 25 \\ AO = 5cm$
Thus..OA=5 cm

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HOPE IT HELPS

@Rêyaañ11