Question

Give the answer I will mark the person brainlist and will also get points.​

Answer 1

we know that,

sum of linear pair is 180°

$\sf : \longrightarrow \: 30 + (2x - 10) + (x + 10) + 15 \: = 180$

$\sf : \longrightarrow \: 30 + 2x - 10 + x + 10 + 15 \: = 180$

$\sf : \longrightarrow \: 45 + 3x \: = 180$

$\sf : \longrightarrow \: 3x \: = 135$

$\sf : \longrightarrow \: x \: = \dfrac{ 135}{3}$

$\sf : \Longrightarrow \: x \: = \bold 45 \degree$

• → 2x - 10
• → 2 × 45 - 10
• → 80

• → x + 10
• → 45 + 10
• → 55

Answer 2

${\large{\bf{\red{\clubs{\underline{\underline{\mathfrak{ Solution:}}}}}}}}$

Concept Used :

Linear Pair : Sum of all angles connected to a same point is 180°.

Than :

${\mapsto{\text{Angle 1 + Angle 2 + Angle 3 + Angle 4 = 180°}}}$

${\leadsto{\sf{30° + ( 2x-10°) + (x +10°) + 15° = 180°}}}$

${\leadsto{\sf{45° + 3x = 180°}}}$

${\leadsto{\sf{3x = 180° - 45°}}}$

${\leadsto{\sf{x = {\cancel\frac{135}{3} }}}}$

${\large{\purple{:{\longmapsto{\underline{\boxed{\bf{X = 45°}}}}}}}}</p><p>$

So,

${\red{\underline{\purple{\underline{\boxed{\red{\mathfrak{X \: is \: 45°}}}}}}}}$

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For Varification :

${\dashrightarrow{\sf{30° + ( 2x-10°) + (x +10°) + 15° = 180°}}}$

${\dashrightarrow{\sf{30° + ( 2 \times 45-10°) + (45+10°) + 15° = 180°}}}$

${\dashrightarrow{\sf{30° + ( 90-10°) + (45+10°) + 15° = 180°}}}$

${\dashrightarrow{\sf{30° +80 ° + 55° + 15° = 180°}}}$

${\red{\mapsto{\underline{\bf{180° = 180°}}}}}$

${\red{\mapsto{\underline{\bf{LHS = RHS}}}}}$

Hence, Varified.

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