Question

Give the answer very very fast and u r brainliest

Answer 1

Answer:mark brainliest

Step-by-step explanation:

D.0

Answer 2

Answer:

Step-by-step explanation:

Given a + b + c = x2x2

Then value of

(x3x3 -2a )3 + (x3x3-2b )3 + ( x3x3 - 2c )3 - 3( x3x3 -2a ) ( x3x3 - 2b ) ( x3x3 - 2c )

We know

x3 + y3 + z3 - 3xyz  = ( x + y + z ) ( x2 + y2 + z​2  - xy - yz - zx  )

So we can see that here

x = ​(x3x3 -2a )

y = ​(x3x3 -2b )

z = ​(x3x3 -2c )

Now , we apply formula nad get

⇒⇒[ ​(x3x3 -2a ) + ​(x3x3 -2b ) + ​(x3x3 -2a ) ] [ ​(x3x3 -2a )2 + ​(x3x3 -2b )2 + ​(x3x3 -2c )2 - ​(x3x3 -2a )​(x3x3 -2b ) - ​(x3x3 -2b )​(x3x3 -2c ) - ​(x3x3 -2c )​(x3x3 -2a ) ]

Let [ ​(x3x3 -2a )2 + ​(x3x3 -2b )2 + ​(x3x3 -2c )2 - ​(x3x3 -2a )​(x3x3 -2b ) - ​(x3x3 -2b )​(x3x3 -2c ) - ​(x3x3 -2c )​(x3x3 -2a ) ]​ = A

So,

⇒⇒[ ​(x3x3 -2a ) + ​(x3x3 -2b ) + ​(x3x3 -2a ) ] A

⇒⇒[ ​x3x3+ x3x3 + x3x3  -2a -2b -2a ] A

⇒⇒[ x -2 ( a + b + c ) ] A

Now As given a + b + c = x2x2 , we get

⇒⇒[ x -2 ( x2x2 )] A

⇒⇒ [ x - x ] A

⇒⇒ 0 ×× A

⇒⇒ 0

So,

(x3x3 -2a )3 + (x3x3-2b )3 + ( x3x3 - 2c )3 - 3( x3x3 -2a ) ( x3x3 - 2b ) ( x3x3 - 2c )  = 0