give the derivation of identityused for
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4
HEY DEAR_______❤❤❤❤❤
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=>IDENTITY....
=>> ( x + y + z )^2
=>(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2yz + 2zx
Proof:
Let x + y = k then,
(x + y + z)^2 = (k + z)^2
= k^2 + 2kz + z^2 (Using identity I)
= (x + y)^2 + 2(x + y)z + z^2
= x^2 + 2xy + y^2 + 2xz + 2yz + z^2
= x^2 + y^2 + z^2 + 2xy + 2yz + 2zx (proved)
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Anonymous:
thanks for brainliest
Answered by
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Holaaa Mate
Answer:
✔️(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2yz + 2zx
✔️Proof:
Let x + y = a then,
(x + y + z)^2 = (a + z)^2
= a^2 + 2az + z^2 (Using identity 1)
= (x + y)^2 + 2(x + y)z + z^2
= x^2 + 2xy + y^2 + 2xz + 2yz + z^2
= x^2 + y^2 + z^2 + 2xy + 2yz + 2zx
HENCE PROVED..
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