Question

Give the equation for the value of g at a depth 'd' from the surface of Earth. What is the value of 'g' at the centre of the earth?

Answer 1

Acceleration due to gravity in depth d from the earth's surface is given by, $g=g_0\left(1-\frac{d}{R}\right)$

where $g_0$ is the acceleration due to gravity on the earth's surface and R is the radius of the earth.

We have to find acceleration due to gravity at the centre of the earth.
at centre of the earth, depth = radius of earth's surface . e.g., d = R

Hence, g = $g_0\left(1-\frac{R}{R}\right)$
g = 0

Hence, value of g will be zero at the centre of the earth.

Answer 2

Answer:

Acceleration due to gravity in depth d from the earth's surface is given by, g=g_0\left(1-\frac{d}{R}\right)g=g

0

(1−

R

d

)

where g_0g

0

is the acceleration due to gravity on the earth's surface and R is the radius of the earth.

We have to find acceleration due to gravity at the centre of the earth.

at centre of the earth, depth = radius of earth's surface . e.g., d = R

Hence, g = g_0\left(1-\frac{R}{R}\right)g

0

(1−

R

R

)

g = 0

Hence, value of g will be zero at the centre of the earth.