Question

Give the expression to calculate the distance covered (s) by a body in time 't'

when : [2]

(i) Body is moving with uniform speed 'v'.

(ii) Body is accelerated by 'a' and starts with velocity 'u'.​

Answer 1

Answer:

t be the time in seconds from the beginning of the motion of a particle. If the particle has a velocity of 4 m/s initially (at t=0) and has a constant acceleration of 2 m/s2, find the velocity of the particle:

when t=1

when t=2

after t seconds.

Draw the velocity–time graph for the motion.

Solution

When t=1, the velocity of the particle is 4+2=6 m/s.

When t=2, the velocity of the particle is 4+2×2=8 m/s.

After t seconds, the velocity of the particle is 4+2t m/s.