Give the expression to calculate the distance covered (s) by a body in time 't'
when : [2]
(i) Body is moving with uniform speed 'v'.
(ii) Body is accelerated by 'a' and starts with velocity 'u'.
Attachments:
Answers
Answered by
1
Answer:
t be the time in seconds from the beginning of the motion of a particle. If the particle has a velocity of 4 m/s initially (at t=0) and has a constant acceleration of 2 m/s2, find the velocity of the particle:
when t=1
when t=2
after t seconds.
Draw the velocity–time graph for the motion.
Solution
When t=1, the velocity of the particle is 4+2=6 m/s.
When t=2, the velocity of the particle is 4+2×2=8 m/s.
After t seconds, the velocity of the particle is 4+2t m/s.
Similar questions
Geography,
3 months ago
Math,
3 months ago
English,
3 months ago
Hindi,
7 months ago
Social Sciences,
7 months ago
Sociology,
10 months ago
Business Studies,
10 months ago