Give the magnitude and direction of the net force acting on a stone of mass 0.1 kga. just after it is dropped from the window of a stationary trainb. just after it is dropped from the window of a train running at a constant velocity of 36 km/hc. just after it is dropped from the window of a train accelerating with 1 ms⁻²d. lying on the floor of a train which is accelerating with 1 m s⁻², the stone being at rest relative to the trainNeglect air resistance throughout.
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◆ Answer with explainations -
Forces acting on mass of 0.1 kg,
(a) Just after it is dropped from the window of a stationary train-
F = mg = 0.1×10 = 1 N vertically downwards
(b) Just after it is dropped from the window of a train running at a constant velocity of 36 km/h -
F = mg = 0.1×10 = 1 N vertically downwards
(c) Just after it is dropped from the window of a train accelerating with 1 m/s^2 -
F = mg = 0.1×10 = 1 N vertically downwards
(d) Lying on the floor of a train which is accelerating with 1 m/s^2, the stone being at rest relative to the train -
F = ma = 0.1×1 = 0.1 N horizontally forwards
Hope that is useful...
◆ Answer with explainations -
Forces acting on mass of 0.1 kg,
(a) Just after it is dropped from the window of a stationary train-
F = mg = 0.1×10 = 1 N vertically downwards
(b) Just after it is dropped from the window of a train running at a constant velocity of 36 km/h -
F = mg = 0.1×10 = 1 N vertically downwards
(c) Just after it is dropped from the window of a train accelerating with 1 m/s^2 -
F = mg = 0.1×10 = 1 N vertically downwards
(d) Lying on the floor of a train which is accelerating with 1 m/s^2, the stone being at rest relative to the train -
F = ma = 0.1×1 = 0.1 N horizontally forwards
Hope that is useful...
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