Question

One end of a string of length l is connected to a particle of mass m and the other two a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle directed towards the centre is
(i) T
(ii) $T- (\frac{mv^2}{I})$
(iii) $T- (\frac{mv^2}{I})$
(iv) 0
T is the tension in the string.

Answer 1

(i) T
When a particle connected to a string revolves in a circular path around a centre, the centripetal force is provided by the tension produced in the string. Hence, in the given case, the net force on the particle is the tension T, i.e.,
F = T = mv2 / l
Where F is the net force acting on the particle

I hope this will help you

Answer 2

Hii friend,

◆ Answer - (1) T

◆ Explaination-
- For a particle moving in circular path with uniform speed, centripetal force acts along radius of path towards centre.
Fc = mv^2/l
- The net force here is cetripeptal force which is nothing but the tension in the string.
Fc = T.

Hope that is useful...