Question

Give the output of the following:-
int a[4]={2,4,6,8};
for(i=0;i<=1;i++)
{
s=a[i]+a[3-i];
System.out.println(s);
}​

Answer 1

Answer:

output for this code segment is

10

10

the loop will run two time since i<=1 for first time i=0(which is less than 1) and second time when i=1 (as it is equal to 1)

in the first iteration

s=a[0]=a[3-0]

=a[0]+a[3] (and we know that indexing in array starts from 0)

= 2+8 = 10 so 10 is printed in first iteration

In the second Iteration

s=a[1]=a[3-1]

=a[1]+a[2]

=4+6 = 10 so 10 is printed in Second iteration

I hope this helped you so plz rate the answer....

Answer 2

Answer:

10

10

Explanation

i Output Remark

0     a[0] + a[3]

⇒ 2 + 8

⇒10 First Iteration

1     a[1] + a[2]

⇒ 4 + 6

⇒10 Second Iteration