Give the ratio of sum of first three term of g.P to the sum of first six term is 125:152?
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In a GP, the ratio of the sum of first 3 terms to the sum of first 6 terms is 125/152. Find the common of the GP.
15/63/56/515/63/56/5

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Answer : (c) 3/5
Explanation:Sn=arn−1r−1inGPExplanation:Sn=arn−1r−1inGP
GiventhatGiventhat
S3S6=a(r3−1/r−1)a(r6−1/r−1)=125/152S3S6=a(r3−1/r−1)a(r6−1/r−1)=125/152
Assumingr≠1Assumingr≠1
(asr−1isindenominatorξdenomitorcannotbe0,r−1≠0,r≠1)(asr−1isindenominatorξdenomitorcannotbe0,r−1≠0,r≠1)
a(r3−1/r−1)a(r6−1/r−1)=125/152a(r3−1/r−1)a(r6−1/r−1)=125/152
r3−1r6−1=125/152r3−1r6−1=125/152
152r3−152=125r6−125152r3−152=125r6−125
125r6−152r3−27=0125r6−152r3−27=0
125r3(r3−1)−27(r3−1=0)125r3(r3−1)−27(r3−1=0)
(125r3−27)(r3−1)=0(125r3−27)(r3−1)=0
125r3=27orr3−1=0125r3=27orr3−1=0
r3=27/125r=1r3=27/125r=1
r=3/5r≠1r=3/5r≠1
Answer=r=3/5iscommonratio.
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Questions >> JEEMAIN and NEET >> Mathematics >> Class11 >> Sequence and Series

Next similar question
Q)
In a GP, the ratio of the sum of first 3 terms to the sum of first 6 terms is 125/152. Find the common of the GP.
15/63/56/515/63/56/5

A)
Need homework help? Click here.
Answer : (c) 3/5
Explanation:Sn=arn−1r−1inGPExplanation:Sn=arn−1r−1inGP
GiventhatGiventhat
S3S6=a(r3−1/r−1)a(r6−1/r−1)=125/152S3S6=a(r3−1/r−1)a(r6−1/r−1)=125/152
Assumingr≠1Assumingr≠1
(asr−1isindenominatorξdenomitorcannotbe0,r−1≠0,r≠1)(asr−1isindenominatorξdenomitorcannotbe0,r−1≠0,r≠1)
a(r3−1/r−1)a(r6−1/r−1)=125/152a(r3−1/r−1)a(r6−1/r−1)=125/152
r3−1r6−1=125/152r3−1r6−1=125/152
152r3−152=125r6−125152r3−152=125r6−125
125r6−152r3−27=0125r6−152r3−27=0
125r3(r3−1)−27(r3−1=0)125r3(r3−1)−27(r3−1=0)
(125r3−27)(r3−1)=0(125r3−27)(r3−1)=0
125r3=27orr3−1=0125r3=27orr3−1=0
r3=27/125r=1r3=27/125r=1
r=3/5r≠1r=3/5r≠1
Answer=r=3/5iscommonratio.
HOPE U LIKE IT!!!! :)
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