Give the reduction of alkenes by sebatier senderen's method?
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Hey there,
Reduction of alkenes and alkynes by Sebatier Senderen's method has following reaction-
RCH=CH2+H2--->RCH2CH3
CH2=CH2+H2--->CH3CH3
CH≡CH+2H2--->CH3CH3
CH3-C≡CH+2H2---->CH3CH2CH3
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07161020
Ace
Reduction of alkenes and alkynes by Sebatier Senderen's method has following reaction-
RCH=CH2+H2--->RCH2CH3
CH2=CH2+H2--->CH3CH3
CH≡CH+2H2--->CH3CH3
CH3-C≡CH+2H2---->CH3CH2CH3
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
Ace
Answered by
1
it is amethod of reduction of alkenes and alynes
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