Chemistry, asked by Radioactive8055, 1 year ago


Give the reduction of alkenes by sebatier senderen's method?

Answers

Answered by 07161020
2
Hey there,

Reduction of alkenes and alkynes by Sebatier Senderen's method has following reaction-

RCH=CH2+H2--->RCH2CH3
CH2=CH2+H2--->CH3CH3
CH≡CH+2H2--->CH3CH3
CH3-C≡CH+2H2---->CH3CH2CH3

PLEASE MARK AS BRAINLIEST IF HELPFUL!!!

Regards
07161020
Ace
Answered by ansh3214
1
it is amethod of reduction of alkenes and alynes
Similar questions