Question

give the solution please please please please please plzz​

Answer 1

Answer:

Given, u = 10 m/s a = - 2m/s²

we know that,

s = ut + ½ at²

= (10)(10) - ½(2)(10)²

= 0 m

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Answer 2

$\huge{\underline{\underline{\mathfrak{\red{AnswEr :-}}}}}$

Given that,

$\longrightarrow$$t = 10 \: sec$

$\longrightarrow$$a = 2 {ms}^{ - 2}$

$\longrightarrow$$u = 10 {ms}^{ - 1}$

$\longrightarrow$From 2nd eq. of motion

$s = ut + \frac{1}{2} a {t}^{2}$

$\longrightarrow$$s = 10 \times 10 + \frac{1}{2} \times 2 \times {10}^{2}$

$\longrightarrow$$s = 100 + 100$

$\longrightarrow$$s = 200 \: m$

Thus, the required distance is 200 m.

$\huge{\underline{\underline{\mathfrak{\red{Thanks}}}}}$