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given:AP=2AB
then
BC=AP/4=
if AP equals to x
then BC=x/4=AC
now,
in right angle triangle APC
tan∅=x/4x
tan∅=1/4
also
tan(∅+beta)=x/2x=1/2
(tan∅+tan beta)/(1+tan∅tanbeta)=1/2
put the value of tan∅
2{1/4+tan(beta)}=1-tan(beta)/4
1/2-1=-tan(beta)/4-2tan(bet)
-1/2=-9tan(beta)/4
tan(beta)=2/9
so, option c)
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