give the structure and geometry of brf5 according to vsepr theory just tell me it will be square bipyramidal or not
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no it will have square planar structure due to one lone pair of electron
shraddha6797:
i have asked for geometry not shape
so octahedral or cubical bipyramidal geometry and sp3d2 hybridisation
thanks
Are you good in physics if i need ur help
no sorry
ok
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BrF5: sp3d2 hybradization having octahedral shape with one position occupied by lone pair (or square pyramidal) with five 4sp3d2-2p bonds.
The valance electrons in BrF5 = 7 + 5 × 7 = 42.
There are six lone pairs of electrons around Br. Hence, the arrangement of these electrons around Br will be octahedral; The hybridization involved in this complex is sp3d2.
The valance electrons in BrF5 = 7 + 5 × 7 = 42.
There are six lone pairs of electrons around Br. Hence, the arrangement of these electrons around Br will be octahedral; The hybridization involved in this complex is sp3d2.
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