Question

Give the symbols of two anions and cations isoelectronic with Ne.

Answer 1

The elements which have the same number of electrons are defined as iso-electronic configuration.

The electronic configuration of $Mg^{2+}$ is $1s^{2} 2s^{2}  2p^{6}$ (which has 8 electrons in the outermost shell)

Its configuration is equal to the nearest inert gas configuration neon. The electronic configuration of neon is $1s^{2}2s^{2}2p^{6}$ which has 8 electrons in the outermost shell. So the  elements which has 8 electrons in the outermost shell are iso-electronic with $Mg^{2+}$.

Thus $Mg^{2+}$  having iso-electronic configuration with $F^{-} and Na^{+}$

The electronic configuration of Na+ is  $1s^{2} 2s^{2}  2p^{6}$.

Answer 2

Answer:-

Mg^ 2 and Na

Hope it helps