give the type of hybridization for each C atom in... 1- CH3-CH2-CH2COOH 2- CH3-CH=CH-CH2-CHO.
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↖⭐Actually welcome to the concept of the Hybridization...
↖⭐Basically in the first compound that is PROPANOIC ACID ...the hydridation of C atom is SP3 ..as the carbon at on has tetrahedral structure and it has no saturated bond in it.....
↖⭐In the Second compound that is Pentan-3 ene - 1al .....that carbon is a Unsaturated carbon thus it has hybridization as SP2 as it is trigonal planer....
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Here is Your Answer.....!!!
____________________________〽
↖⭐Actually welcome to the concept of the Hybridization...
↖⭐Basically in the first compound that is PROPANOIC ACID ...the hydridation of C atom is SP3 ..as the carbon at on has tetrahedral structure and it has no saturated bond in it.....
↖⭐In the Second compound that is Pentan-3 ene - 1al .....that carbon is a Unsaturated carbon thus it has hybridization as SP2 as it is trigonal planer....
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