How many term of the A.P. 2,6,10.....are needed to make the sum 288
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Sn = n/2(2a + (n-1)d)
288 = n/2 (2×2 +(n-1)4)
288 ×2 =n (4+4n-4)
576= n ×4n
576=4n^2
144= n^2
n =12
Therefore the no.of terms are 12
Sn = n/2(2a + (n-1)d)
288 = n/2 (2×2 +(n-1)4)
288 ×2 =n (4+4n-4)
576= n ×4n
576=4n^2
144= n^2
n =12
Therefore the no.of terms are 12
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