Find 249*251 without actual multipication.
ankit292:
250 square minus 1 square
Answers
Answered by
6
249 × 251
= (250 - 1)(250+1)
= (250)^2 - (1)^2 [ (a+b)(a-b) = a^2 - b^2]
= 62500 - 1
= 62499
= (250 - 1)(250+1)
= (250)^2 - (1)^2 [ (a+b)(a-b) = a^2 - b^2]
= 62500 - 1
= 62499
Answered by
1
Similar questions