Physics, asked by ŠÀHÎŁĞÀÚĐ, 1 year ago

give x=4t2-15t+25 find at t=0? find position velocity acceleration

Answers

Answered by Gargihazra
2
When t=0

x=25m

by using differeciation nxn-1

velocity=dx/dt= 2*4*t-1 *15



v=dx/dt =8t-15

t=o

v=-15m/s

a=dv/dt

v=8t-15

=8-0

=8m/s2
hope it helps you..

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