Question

Given

1- Cu2+ + 2e- ----- Cu, E(standard) = 0.337V

2- Cu2+ + e- ------- Cu+ , E(standard) = 0.153V

Electrode potential , E(standard) for the reaction , Cu+ + e- ------ Cu, will be

1- 0.38V 2- 0.52V

3- 0.90V 4-0.30V

Answer 1

- Cu2+ + e- ------- Cu+ , E( standard) = 0.153V. Electrode potential , E( standard) for the reaction , Cu+ + e- ------ Cu, will be ... ​Cu2+ + 2e-→Cu Eº1 = 0.337 V

Answer 2

Answer: 0.52 v

Explanation:cu2+/cu E= 0.337 v

cu2+/cu+ E1=0.153 v

cu+/cu E2 =?

G = G1 +G2

nfE = nfE1 +nfE2 (f will cancel with common)

2*0.337 =1*0.153 +1*E2

0.674 = 0.153 + E2

E2 = 0674 -0.153 = 0.521

E 2 = 0.52 v